X^2+29x+190=0

Solution for X^2+29x+190=0 equation:

X^2+29X+190=0

a = 1; b = 29; c = +190;
Δ = b2-4ac
Δ = 292-4·1·190
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-9}{2*1}=\frac{-38}{2}
=-19
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+9}{2*1}=\frac{-20}{2}
=-10
$